Homework Three

19 $N=0$ (stable), $N=-a/b$ (unstable)

20 $N=0$ (unstable), $N=1$ (stable), $N=2$ (unstable).

21

(a) The only equilibrium is $N=0$,

(c)

\begin{displaymath}N=\frac{N_0 + (1-N_0) k t}{1+(1-N_0)k t}.\end{displaymath}

22 $N=-1$ (stable), $N=0$ (unstable), $N=1$ (stable).

23 $N=-2$ (unstable), $N=0$ (semistable), $N=2$ (stable).

24

(a)


\begin{displaymath}N_{12} = \frac{k}{2}\pm\sqrt{\frac{k^2}{4} - \frac{k h}{r}},\end{displaymath}

where $4 h < k R$ implies real positive discriminant.

(b) $N^2$ has negative value, parabola has a maximum, left root is unstable, right is stable.

25


\begin{displaymath}y(x) = C_1 e^{-3x} + C_2 e^x.\end{displaymath}

26


\begin{displaymath}y(x) = C_1 + C_2 e^{-5x}.\end{displaymath}

27

\begin{displaymath}y(x) = C_1 e^{ (1+\sqrt{3})x} + C_2 e^{(1-\sqrt{3})x}.\end{displaymath}

28


\begin{displaymath}y(x) = C_1 e^{-9x} + C_2e^x.\end{displaymath}


\begin{displaymath}y(x) = \frac{1}{10} e^{-9x} + \frac{9}{10}e^x.\end{displaymath}

29

\begin{displaymath}y = C_1 e^x \cos \sqrt{5} x + C_2 e^x \sin \sqrt{5}{x}.\end{displaymath}

30

\begin{displaymath}y(x) = C_1 e^{-x} \cos{x} + C_2 s^{-x} \sin {x}. \end{displaymath}

31

\begin{displaymath}y(x) = C_1 e^{-3x}\cos 2 x + C_2 s^{-3x} \sin 2 x.\end{displaymath}

32

\begin{displaymath}y(x) = C_1 e^{-2 x} \cos x + C_2 e^{-2 x} \sin x, \end{displaymath}


\begin{displaymath}C_2 = 2 C_1 = 2.\end{displaymath}

33

\begin{displaymath}y(x) = C_1 e^x + C_2 x e^x.\end{displaymath}

34

\begin{displaymath}y(x) = C_1 e^{2x} + C_2 x e^{3x}.\end{displaymath}

Dr Yuri V Lvov 2017-12-10